Question

I NEED HELP PLEASEEEEEEEEEEEEE (I'm giving 35 points)

Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the squares shares one side with the rectangle. The total area of the constructed figure is 120 cm2. What is the perimeter of the rectangle?
Thank you to whoever answers :D

Answer 1

Answer: 18 Centimeters

Step-by-step explanation: The area of the figure is

2x^2 + 2(x+5)^2 + x(x+5)

= 2x^2 + 2x^2 + 20x + 50 + x^2 + 5x

= 5x^2 + 25x + 50,

and this is 120 cm^2,

so x^2 + 5x + 10 = 24 =>

x^2 + 5x - 14 = 0 =>

x = 2, (as x can't be -7).

The perimeter of the original rectangle is

4+14=18 CM