Question

Plz help!!!!!!!!!!!!!

Answer 1

the third one

Explanation:

-b to start is -(-6) which is 6

needs the plus and minus

the first expression is the whole numerator

Answer 2

Answer:
`\bold{c)\quad x=(6\pm √((-6)^2-4(3)(8)))/(2(3))}`

Explanation:

`3x^2-6x+8=0\quad \rightarrow \quad a=3,\ b=-6,\ c=8\\\\\text{Quadratic formula is: }x=(-b\pm √(b^2-4ac))/(2a)\\\\\\x=(-(-6)\pm √((-6)^2-4(3)(8)))/(2(3))}\\\\\\x=(6\pm √((-6)^2-4(3)(8)))/(2(3))`