Question

Plz help me!!!!!!!!!

Answer 1

Answer:
`\bold{(4\pm √(6))/(2)}`

Explanation:

`(3)/(y-2)-2=(1)/(y-1)\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\(3)/(y-2)(y-2)(y-1)-2(y-2)(y-1)=(1)/(y-1)(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=(-b\pm √(b^2-4ac))/(2a)\\\\\\x=(-(-8)\pm √((-8)^2-4(2)(5)))/(2(2))\\\\\\.\ =(8\pm √(64-40))/(2(2))`

`.\ =(8\pm √(24))/(2(2))\\\\\\.\ =(8\pm 2√(6))/(2(2))\\\\\\.\ =(4\pm √(6))/(2)`