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2x-y=4
3y-3x=6
How do I graph this

asked
User Glenbot
by
8.2k points

2 Answers

3 votes

Explanation:

Put y's on the one side and divided by what they have in the front so it would be

y=2x-4

and

y=x+2

and they y intercept for first one is -4

and slope is 2 which it goes up twice and goes right once because its positive

second one, y intercept is 2

and slope is 1 goes one up and one right because it is positive

answered
User Altrim
by
7.8k points
3 votes

Answer:

See the attached image

Explanation:

You must graph the system of equations. To do so, find the intersection points of each line with the axes.

2x-y=4 intersection with the x axis. -----y=0

2x = 4

x = 2.

2x-y=4 intersection with the y axis. -----x=0

-y = 4

y = -4.

Now we have

3y-3x=6 intersection with the x axis. -----y=0

-3x = 6

x = -2

3y-3x=6 intersection with the y axis. -----x=0

3y = 6

y = 2.

Now you can graph both lines. The solution the system will be the intersection of both lines

2x-y=4 3y-3x=6 How do I graph this-example-1
answered
User Rukshan
by
8.6k points

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