Question

(40pts)

SinA sinB = 1/2 * (cosA cosB + sinA sinB - cosA cosB + sinA sinB)

How do I get from this ^^ to

SinA sinB = 1/2 * (2 * sinA sinB)

Need someone who can explain how to do it plz!!

Answer 1

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷ Just work with what is inside the parenthesis

Also, move around the terms to help it make more sense:

(cosA cosB - cosA cosB + sinA sinB + sinA sinB)

As you can see, the 'cosA cosB' would cancel out through subtraction.

Now we have this:

(sinA sinB + sinA sinB)

This is just two sets of sinA sinB so it can be written as:

(2 * sinA sinB)

Simply place the values outside the parenthesis back there to get the answer

SinA sinB = 1/2 * (2 * sinA sinB)

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡