Question

Select the correct answer

Answer 1

16

2

Explanation:

Given in the question an equation

`(x^2 - 10x + 14)/( x-8)`

The constant term that the numerator must have = 16

To get this number add 2 in the numerator

after which the equation will become

`(x^2 - 10x + 14+2)/( x-8)`

`(x^2 - 10x + 16)/( x-8)\\`

Now by using factorisation of quadratic equation we have

`((x-8)(x-2))/(x-8)`

(x-2)

but if we add and subtract 2 in the numerator then

`(x^2 - 10x + 16 -2)/( x-8)`

`((x-8)(x-2)-2)/(x-8)`

`(x-2)-(2)/(x-8)`