Question

Use the graph below to answer the question that follows:

cosine graph with points at 0, negative 1 and pi over 2, 3, and pi, negative 1

What are the amplitude, period, and midline of the function?

Answer 1

For this case the amplitude is given by:

A = (l-5l + 3) / 2

A = 8/2

A = 4

The middle line is given by:

y = -1

The period of the function is given by:

T = l x2 - x1 l

T = l 0 - 2pi l

T = l - 2pi l

T = 2pi

Answer:

Amplitude: 4; period: 2π; midline: y = -1

Explanation:

pi