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4 votes
What is the sum of the arithmetic series below 2+5+8+...+56​

asked
User Raffo
by
7.5k points

1 Answer

2 votes

Answer:

551

Explanation:

The sum to n terms of an arithmetic sequence is


S_(n) =
(n)/(2)( first + last)

The number of terms is


a_(n) = a + (n - 1)d ← d is the common difference, a is the first term

d = 5 - 2 = 8 - 5 = 3, hence

2 + 3(n - 1) = 56

2 + 3n - 3 = 56

3n - 1 = 56 ⇒ 3n = 57 ⇒ n = 19


S_(19) =
(19)/(2) ( 2 + 56 ) = 19 × 29 = 551

answered
User Helmut Grohne
by
8.2k points

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