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The equation of the parabola whose focus is at (7, 0) and directrix at x = -7 is: y = (1/28)x² x = (1/28)y² x = -(1/28)y²

The equation of the parabola whose focus is at (7, 0) and directrix at x = -7 is: y = (1/28)x² x = (1/28)y² x = -(1/28)y²
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The equation of the parabola whose focus is at (7, 0) and directrix at x = -7 is:

y = (1/28)x²
x = (1/28)y²
x = -(1/28)y²

asked
User Ugosan
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1 Answer

4 votes

the answer is x=(1/28)y^2

answered
User Jan Olaf Krems
by
7.8k points
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