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Find the exact value of sine, cosine, and tangent of A and T for each triangle.

Find the exact value of sine, cosine, and tangent of A and T for each triangle.-example-1

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Answer:

See below

Explanation:

7)

AT² = 11² + 4² = 121 + 16 = 137

AT = √137

sinA = DT/AT = 11/√137 = (11√137)/137

cosA = AD/AT = 4/√137 = (4√137)/137

tanA = DT/AD = 11/4

sinT = AD/AT = 4/√137 = (4√137)/137

cosT = DT/AT = 11/√137 = (11√137)/137

tanT = AD/DT = 4/11

9)

AT² = 8² + 3² = 64 + 9 = 73

AT = √73

sinA = LT/AT = 8/√73 = (8√73)/73

cosA = AL/AT = 3/√73 = (3√73)/73

tanA = LT/AL = 8/3

sinT = AL/AT = 3/√73 = (3√73)/73

cosT = LT/AT = 8/√73 = (8√73)/73

tanT = AL/LT = 3/8

11)

6² = 4² + RT²

36 = 16 + RT²

RT² = 20

RT =√20 = √(4× 5) = 2√5

sinA = RT/AT = (2√5)/6 = (√5)/3

cosA = AR/AT = 4/6 = 2/3

tanA = RT/AR = (2√5)/4 = (√5)/2

sinT = AR/AT = 4/6 = 2/3

cosT = RT/AT = (2√5)/6 = (√5)/3

tanT = AR/RT = 4/(2√5) = (2√5)/5

answered
User Jake Worth
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