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Part A: The product of (n2 – 6n + 3) and -4n is

A. -4n^3+24n^2+12n
B. -4n^3+24n^2-12n
C. 4n^3+24n^2-12n

Part B: When this product is multiplied by -n, the result is
A. 4n^4-24n^3+12n^2
B. -4n^4+24n^3+12n^2
C. 4n^4+24n^3+12n^2

1 Answer

4 votes

Answer:

Part A) Option B.
-4n^(3)+24n^(2)-12n

Part B) Option A.
4n^(4)-24n^(3)+12n^(2)

Explanation:

Part A) we have


(n^(2)-6n+3)(-4n)

the product is equal to


=(n^(2))(-4n)-6n(-4n)+3(-4n)\\=-4n^(3)+24n^(2)-12n

Part B) When this product is multiplied by -n, the result is

we have


(-4n^(3)+24n^(2)-12n)(-n)


=(-4n^(3))(-n)+24n^(2)(-n)-12n(-n)\\=4n^(4)-24n^(3)+12n^(2)

answered
User Kevinmrohr
by
8.2k points
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