asked 190k views
1 vote
Find the range of y=4sin2x+3

2 Answers

3 votes

Answer:

-1,7

Explanation:

got it right on odessyware

answered
User OverclockedTim
by
7.8k points
0 votes

Answer:

[-1, 7]

Explanation:

If you mean ...

y = 4sin(2x) +3

then you can substitute the range of the sine function into the equation and evaluate it to find the range of y.

The range of sin( ) is [-1, 1], so the range of y is ...

4[-1, 1] +3 = [4(-1)+3, 4(1)+3] = [-1, 7]

_____

Comment on the problem statement

The range of y = 4sin²(x)+3 will be different, and the range of 4sin(2x+3) will be different yet. It is usually a good idea to use parentheses around function arguments.

answered
User Nikolay Makhonin
by
7.8k points

Related questions

2 answers
2 votes
125k views
asked Sep 1, 2020 8.5k views
Bhiefer asked Sep 1, 2020
by Bhiefer
8.5k points
2 answers
1 vote
8.5k views
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.