Question

An angle, θ, is in standard position. The terminal side of the angle passes through the point (6, -5).

Find sinθ.

Answer 1

-5 square root of 51/51

Answer 2

`Sin\theta =(-5)/(√(61))`

Explanation:

(6, -5)

According to the diagram

`OA^(2)=OB^(2)+AB^(2)`

`OA^(2)=6^(2)+5^(2)=36+25=61`

`OA=√(61)`

`Sin\theta =(AB)/(OA)`

`Sin\theta =(-5)/(√(61))`