Question

Please help me! I would really appreciate it

Answer 1

D

Explanation:

Using the rule of exponents

`(a^nb^n)^(m)` =
`a^((mn))`
`b^((mn))`, hence

(
`a^{(1)/(2) }`
`b^{(1)/(3) }`)^(
`(1)/(2)`)

=
`a^{(1)/(2)((1)/(2) ) }` ×
`b^{(1)/(3)((1)/(2))  }`

=
`a^{(1)/(4) }`
`b^{(1)/(6) }` → D