Question

What equation is equivalent

Answer 1

`\large\boxed{(2-(1)/(y))/(3+(1)/(y))=(2y-1)/(3y+1)}`

Explanation:

`(2-(1)/(y))/(3+(1)/(y))=\left((2y)/(y)-(1)/(y)\right):\left((3y)/(y)+(1)/(y)\right)=(2y-1)/(y):(3y+1)/(y)=(2y-1)/(y)\cdot(y)/(3y+1)\\\\=(2y-1)/(3y+1)`