Question

How many moles are in 594 grams of Pb(NO3)4

Answer 1

Molar mass(Pb(NO3)4) =

= 207.2 × 1 + 14 × 4 + 16 × 12 =

= 455.2 g/mol

n(Pb(NO3)4) = 594 g ÷ 455.2 g/mol ~

~ 1.3 mol