Question

What are the coordinates of the vertex of the function below? Write your answer in the form (x,y).

Answer 1

vertex is (5,11).

Explanation:

We have given a equation.

y-11 = -(x-5)²

We have to find the vertex of the function.

y = a(x-h)²+k is vertex form of quadratic equation where (h,k) is vertex of equation.

Adding 11 to both sides of given equation, we have

y-11+11 = -(x-5)²+11

y = -(x-5)²+11

Comparing to the vertex form, we have

h = 5 and k = 11

Hence, vertex is (5,11).

Answer 2

The vertex is

`(5,11)`

EXPLANATION

The given function is

`y - 11 = - {(x - 5)}^(2)`

Rewrite in the form;

`y = - {(x - 5)}^(2) + 11`

This function is in the form;

`y = a {(x - h)}^(2) + k`

where

`(h,k)=(5,11)`

is the vertex