Question

What would be the pH of a solution whose [OH-] is 2.8 × 10-5M?

Answer 1

pOH= - log [OH-]

pOH=-log[2.8E-5]

pOH= 4.55

pOH + pH= 14

pH= 14 - 4.55

pH= 9.45

SORRY IF THIS IS WRONG