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What is the KE of a 13kg boulder moving at 78.3m/s?

What is the KE of a 13kg boulder moving at 78.3m/s?
asked 30.3k views
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What is the KE of a 13kg boulder moving at 78.3m/s?

asked
User Salandur
by
9.3k points

2 Answers

11 votes

Answer:

KE =


(1)/(2) m {v}^(2) \\

Step-by-step explanation:


ke = (1)/(2) m {v}^(2) \\ = (1)/(2) * 13 * {78 . 3}^(2) \\ ke = 39850.785j \\

answered
User Vinoth A
by
8.1k points
3 votes

Answer:

39850.785 J

Step-by-step explanation:

0.5 x m x v^2

0.5x13x78.3^2

answered
User Lliane
by
7.7k points
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