Question

Find the equation of a circle whose center is at (-8 , -3) and radius 2

Answer 1

`(x+8)^(2) +(y+3)^(2)=4`

Explanation:

we know that

The equation of the circle in center radius form is equal to

`(x-h)^(2) +(y-k)^(2)=r^(2)`

where

(h,k) is the center of the circle

r is the radius

In this problem we have

`(h,k)=(-8,-3)`

`r=2\ units`

substitute

`(x+8)^(2) +(y+3)^(2)=2^(2)`

`(x+8)^(2) +(y+3)^(2)=4`