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What is (18y^4+6y^2-24) Divided by (3y-6) using synthetic division? plz explain

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Start by dividing by 3 (LCD) then add missing y-terms. Use 2 as divisor since y-2=0 gives y=2. Write the coefficients, including the added 0’s. Remember to leave space and bring down the leading coefficient. Then multiply each term by the divisor and add to the next coefficient. Then, taking your answers at the bottom, add back the variables, subtracting one exponent. The remainder is written as a fraction with y-2 as the denominator.
What is (18y^4+6y^2-24) Divided by (3y-6) using synthetic division? plz explain-example-1
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