Question

Who knows how to do this ughhh I need help!

Answer 1

`\large\boxed{\sqrt{56x^(17)}=2x^8√(14x)}`

Explanation:

`Domain:\ x\geq0\\\\\sqrt{56x^(17)}=\sqrt{4\cdot14\cdot x^(16+1)}\\\\\text{use}\ a^n\cdot a^m=a^(n+m)\\\\=\sqrt{4\cdot14\cdot x^(16)\cdot x^1}\\\\\text{use}\ √(ab)=√(a)\cdot√(b)\\\\=\sqrt4\cdot√(14)\cdot\sqrt{x^(16)}\cdot√(x)=2\cdot√(14)\cdot\sqrt{x^(8\cdot2)}\cdot√(x)\\\\\text{use}\ (a^n)^m=a^(nm)\\\\=2\cdot√(14)\cdot√((x^8)^2)\cdot√(x)\\\\\text{use}\ √(a^2)=a\ \text{for}\ a\geq0\\\\=2\cdot√(14)\cdot x^8\cdot√(x)=2x^8√(14x)`