What is the sine of angle x ?

Question

asked Feb 8, 2020 81.2k views

2 Answers

Alexandru Dinu · Answer 1 · 2020-02-11T14:37:25+0000

The answer is:
sin(x)=(b)/(c)

Since it's a right triangle, we can determine the Sine of the angle "x" using the following formula:

sin(x)=(b)/(c)

Where:

$b=opposite\\a=hypotenuse$

Also, we can determine the cosine and the tangent of the same angle "x" using the following formulas:

$cos(x)=(a)/(c) \\tan(x)=(b)/(a)$

Where:

$a=hypotenuse\\b=opposite\\c=adjacent$

Have a nice day!

Navaneet · Answer 2 · 2020-02-14T14:07:34+0000

Answer:
sinx=(b)/(c)

Explanation:

By definition you have that:

$sin\alpha=(opposite)/(hypotenuse)$

Based on the figure attached in the problem you have that:

$\alpha=x\\opposite=b\\hypotenuse=c$

Therefore, you must substitute the above into
$sin\alpha=(opposite)/(hypotenuse)$

Then, the answer is:

sinx=(b)/(c)