Question

Plz answer quickly...

Find the probability.?
A box of chocolates contains five milk chocolates and seven dark chocolates.Four of the milk chocolates and one of the dark chocolates have peanuts inside. You randomly select and eat a chocolate.It is a milk chocolate or has peanuts inside.

Answer 1

Answer:Total number of chocolates

9+3+6 = 18

The probability that she chose a MC is the number of Mc in the box of chocolate divided by the total number of chocolates

9/18

The probability that she chose a DC from the box is

3/18 = 1/6

Answer 2

Answer: Our required probability is 0.83.

Explanation:

Number of milk chocolates = 5

Number of dark chocolates = 7

Number of peanut among milk chocolate = 4

Number of peanut among dark chocolate = 1

We need to find the probability that .It is a milk chocolate or has peanuts inside.

P(Milk chocolate) + P(peanut)

`(5)/(12)+(5)/(12)\\\\=(10)/(12)\\\\=0.83`

Hence, our required probability is 0.83.