Question

A tile pattern on a wall is made up of two identical parallelograms and three identical triangles. What is the area of the tile pattern? Enter your answer in the box.

Answer 1

So,

The area of a parallelogram is simply base times height, or BH. So, the area of the two parallelograms is 2BH.

The area of a triangle is 1/2bh (to distinguish the triangle's b and h from the parallelogram's). Therefore, the area of the three triangles is 3/2bh.

Adding up all of the areas, we get A = 2BH + 3/2bh.

`total\ blades=(100\ blades)/(12in.^2)*(144\ in.^2)/(ft.^2)*A_T`

`(100\ blades)/(12in.^2)*(144\ in.^2)/(ft.^2)=(1.2*10^2\ blades)/(ft.^2)`

`(2\ ft.)/(pace)`

`A_T=A_Q+A_R`

`A_Q=(3)/(4)(8\ paces*(2\ ft.)/(pace))^2=48\ ft.^2`

`A_R=14\ paces*(2\ ft.)/(pace)*7\ paces*(2\ ft.)/(pace)=392\ ft.^2`

`A_T=392+48\approx4.5*10^2\ ft.^2`

`(1.2*10^2\ blades)/(ft.^2)*4.5*10^2\ ft.^2=5.4*10^4\ blades`

Answer 2

if this question is for K12 is 448 your correct answer.

18in / 10in/ 14in = 448

I did the test and this is the right answer

I hope this helps.