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Two positive charges are seperated by 12 cm. The force thatq1 exerts on q2 is 4×10 ^8N. what is this force if the distance between the two charges is reduced to 9cm?​

Two positive charges are seperated by 12 cm. The force thatq1 exerts on q2 is 4×10 ^8N. what is this force if the distance between the two charges is reduced to 9cm?​
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Two positive charges are seperated by 12 cm. The force thatq1 exerts on q2 is 4×10 ^8N. what is this force if the distance between the two charges is reduced to 9cm?​

Two positive charges are seperated by 12 cm. The force thatq1 exerts on q2 is 4×10 ^8N-example-1
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User Alexey Kosov
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1 Answer

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The new force is 7.11 x 10^8 N.

answered
User Dimitri Merejkowsky
by
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