Need help please and thank you. 1. Solve. 8x^2+5=35. Round to the nearest hundredth. Enter your answers in the boxes. The solutions are approximately and . 2. Solve. 0=x^2+14x+4…

Question

asked Feb 25, 2020 26.2k views

2 Answers

Enrique Moreno Tent · Answer 1 · 2020-03-01T02:22:54+0000

Answer:

Part 1) The solutions are approximately
x=1.94 and
x=-1.94

Part 2) The solutions are
x=-4 and
x=-10

Explanation:

Part 1)

in this problem we have

8x^(2) +5=35

8x^(2)=35-5

8x^(2)=30

x^(2)=30/8

square root both sides

$x=(+/-)√((30/8))\\ \\x=(+/-)1.94$

The solutions are
x=1.94 and
x=-1.94

Part 2)

we know that

The formula to solve a quadratic equation of the form
ax^(2) +bx+c=0 is equal to

$x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}$

in this problem we have

0=x^(2) +14x+40

so

$a=1\\b=14\\c=40$

substitute in the formula

$x=\frac{-14(+/-)\sqrt{14^(2)-4(1)(40)}} {2(1)}$

$x=\frac{-14(+/-)√(36)} {2}$

$x=\frac{-14(+/-)6} {2}$

$x=\frac{-14(+)6} {2}=-4$

$x=\frac{-14(-)6} {2}=-10$

The solutions are
x=-4 and
x=-10