Question

When a child fires an air gun that discharges a 0.35 g steel pellet at a velocity of 162 km/h, what is the wavelength in meters of the pellet?

Answer 1

`4.2\cdot 10^(-32) m`

Step-by-step explanation:

The De Broglie's wavelength of an object is given by:

`\lambda=(h)/(mv)`

where

h is the Planck constant

m is the mass of the object

v is the speed of the object

In this problem, we have:

`m=0.35 g=3.5\cdot 10^(-4) kg` is the mass of the pellet

`v=162 km/h=45 m/s` is the speed of the pellet

Substituting into the equation, we find the wavelength of the pellet:

`\lambda=(6.63\cdot 10^(-34) Js)/((3.5\cdot 10^(-4)kg)(45 m/s))=4.2\cdot 10^(-32) m`