Question

I tried to do this problem but got stuck can someone please help???

Answer 1

`216 + x = x(x {}^(2) - 5) + 6x`

`216 + x = x {}^(3) - 5x + 6x`

Add like terms

`216 + x = x {}^(3) + x`

Subtract x form both sides and they both cancel out

`216 = x {}^(3)`

Subtract 216 from both sides

`216 - x {}^(3) = 0`

Plug in your calculator, in your "y=" and look at your zeros and *check if they equal each other by substituting x with the zeros and that ones that work is your answer.

Answer 2

Answer: x = 6

Explanation: