Question

Given that g(x)=2x^2-5. Calculate g(x+4)+2

Answer 1

`2x^2+16x+29`

Explanation:

Given that,

`g(x)=2x^2-5`

We need to find g(x+4)+2

`g(x+4)=2(x+4)^2-5\\\\=2(x^2+16+8x)-5\\\\=2x^2+32+16x-5\\\\=2x^2+16x+27`

Now,

`g(x+4)+2=2x^2+16x+27+2\\\\=2x^2+16x+29`

So, the value of
`g(x+4)+2` is
`2x^2+16x+29`