Question

I give a crown please help me
!

Answer 1

x < 0.5

Explanation:

`\text{We know:}`

`(a+b)^k> a^k+b^k\ for\ k>1\\\\and\\\\(a+b)^k< a^k+b^k\ for\ k<1\\\\\text{we have}\\\\\underbrace{(0.5)^(2x)}_(a^k)+\underbrace{(0.3)^(2x)}_(b^k)>\underbrace{(0.8)^(2x)}_((a+b)^k)\ \text{therefore}\ 2x<1\qquad\text{divide both sides by 2}\\\\x<0.5`