Question

Find f'(0) for the function. Provide an exact answer (meaning no rounding is involved).

Answer 1

The derivative of a function like this is computed with the following formula:

`(e^(f(x)))' = e^(f(x))\cdot f'(x)`

So, in your case, we have

`f'(x) = e^(x^2+17x) \cdot (2x+17)`

When you evaluate this at 0, you have

`f'(0) = e^0 \cdot 17 = 1\cdot 17=17`