Question

What is the sum? 3x/x-4 + x-3/2x

Answer 1

`(7x^2-7x+12)/(2x(x-4))`

Explanation:

Given

`(3x)/(x-4)` +
`(x-3)/(2x)`

Before we can add the fractions we require them to have a common denominator.

Multiply the numerator/denominator of the left fraction by 2x

Multiply the numerator/denominator of the right fraction by (x - 4)

=
`(3x(2x))/(2x(x-4))` +
`((x-3)(x-4))/(2x(x-4))`

Distribute and simplify the numerators leaving the denominator

=
`(6x^2+x^2-7x+12)/(2x(x-4))`

=
`(7x^2-7x+12)/(2x(x-4))`

Answer 2

The answer is
`(7x^(2)-7x+12 )/(2x^(2)+8x )`²

Explanation:

See the attached image for solution