Answer:
The smallest zero is -3
Explanation:
h(x) = 4x^2 - 8x-60
To find the zero's we set the function equal to zero
0 = 4x^2 - 8x-60
Factor out a 4
0 =4(x^2 -2x-15)
What number multiplies to -15 and adds to -2
-5*3 = -15
-5+3 = -2
0 =4(x-5)( x+3)
Using the zero product property
0 = x-5 0=x+3
x=5 x=-3
The smallest zero is -3