Question

Ax-bx+y=z solve for x​

Answer 1

`\bold{Answer}`

`\boxed{\bold{x=(z-y)/(A-b);\quad \:A\\e \:b}}`

`\bold{Explanation}`

• 
  `\bold{Solve: \ Ax-bx+y=z}`

`\bold{-------------------}`

• 
  `\bold{Subtract \ Y \ From \ Both \ Sides}`

`\bold{Ax-bx+y-y=z-y}`

• 
  `\bold{Simplify}`

`\bold{Ax-bx=z-y}`

• 
  `\bold{Factor \ Ax-bx: \ x\left(A-b\right)}`

`\bold{x\left(A-b\right)=z-y}`

• 
  `\bold{Divide \ Both \ Sides \ By \ A-b;\quad \:A\\e \:b}`

`\bold{(x\left(A-b\right))/(A-b)=(z)/(A-b)-(y)/(A-b);\quad \:A\\e \:b}`

• 
  `\bold{Simplify}`

`\bold{(x\left(A-b\right))/(A-b)=(z)/(A-b)-(y)/(A-b);\quad \:A\\e \:b}`

`\boxed{\bold{Eclipsed}}`

Answer 2

This question requires us to change the subject of a formula. This can be achieved by following the order of operations in reverse. First, isolate the terms with our variable of interest, x:

ax - bx = z - y

Then, we take x out as it is being multiplied to both a and b:

x(a - b) = z - y

Dividing (a - b) on both sides, we get:

x = (z - y) / (a - b)

Thus, the answer is x= z-y/a-b

Explanation: