Question

A hula hoop has a three foot diameter how far will it travel in 6 revolution

Answer 1

It will travel 56.52 ft in 6 revolution.

Explanation:

We know that Circumference of circle = 2πr

where diameter is already given so by putting it in the formula we get the following result for radius(r)

Diameter = 3 ft

Therefore the radius r = diameter/2 = 3/2 = 1.5 ft

So circumference of loop is:

Circumference = 2πr = 2 * 3.14 * 1.5 = 9.42 ft

We have to find the distance traveled in 6 revolution

As we know that distance traveled in one revolution = 9.42 ft

So distance traveled in 6 revolution = 6 * 9.42 = 56.52 ft

Answer 2

Distance traveled in 6 revolution = 56.52 ft

Explanation:

Formula:

Circumference of circle = 2πr

r - Radius of circle

It is given that,

A hula hoop has a three foot diameter.

Diameter = 3 ft

Therefore the radius r = diameter/2 = 3/2 = 1.5 ft

To find the circumference of loop

r = 1.5 ft

Circumference = 2πr = 2 * 3.14 * 1.5 = 9.42 ft

To find the distance traveled in 6 revolution

Distance traveled in one revolution = 9.42 ft

Distance traveled in 6 revolution = 6 * 9.42 = 56.52 ft