Question

What is an equation of the line that is perpendicular to y+1-3x-5 and passes through the point 4,-6

Answer 1

`y + 6 = (1)/(3)(x-4)`

Explanation:

A perpendicular line is a line whose slope is the negative reciprocal of the other line. The line y + 1 = -3x - 5 has slope -3. This means the line perpendicular will be 1/3.

Substitute 1/3 and (4.-6) into the point slope form of a line.

`y - y_1 = m(x-x_1)\\y --6 = (1)/(3)(x - 4)\\y + 6 = (1)/(3)(x-4)`