Question

The volume of gas in a ballon is 1.90L at 21.0C. The balloon is heated, causing it to expand to a volume of 5.70L. What is the new temperature of the gas into the ballon

Answer 1

New temperature:

• 882.45 K, which is the same as
• 609.3 °C.

Step-by-step explanation

By Charles's Law,

`V \propto T`,

where

• V is the volume of an ideal gas, and
• T is the absolute temperature of the gas.

In other words,

`(V_2)/(V_1) = (T_2)/(T_1)`,

`T_2 = T_1\cdot(V_2)/(V_1)`

`T_1 = 21.0\;\textdegree{}\text{C}=(21.0 + 273.15)\;\text{K}`.

`T_2 =T_1\cdot(V_2)/(V_1) = (21.0 + 273.15)\;\text{K}*\frac{5.70\;\text{L}}{1.90\;\text{L}}=882.45\;\text{K}`.

`882.45\;\text{K} = (882.45 - 273.15)\;\textdegree{}\text{C}=609.3\;\textdegree{}\text{C}`.