Question

Leg-9.7 km

hypo-10 km


What is the perimeter? If necessary, round to the nearest tenth.

Answer 1

`\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies √(c^2-a^2)=b \qquad \begin{cases} c=\stackrel{hypotenuse}{10}\\ a=\stackrel{adjacent}{9.7}\\ b=opposite\\ \end{cases} \\\\\\ √(10^2-9.7^2)=b\implies √(5.91)=b\implies 2.43\approx b \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter}}{10+9.7+2.43}\implies 22.13`