Select the two values of x that are Roots of this equation 2x-3=-5x^2

Question

asked Feb 21, 2020 83.9k views

2 Answers

Kamokaze · Answer 1 · 2020-02-25T19:05:16+0000

Answer:

The roots are -1 and 0.60

Explanation:

we know that

The formula to solve a quadratic equation of the form
ax^(2) +bx+c=0 is equal to

$x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}$

in this problem we have

2x-3=-5x^(2)

so

5x^(2)+2x-3=0

$a=5\\b=2\\c=-3$

substitute in the formula

$x=\frac{-2(+/-)\sqrt{2^(2)-4(5)(-3)}} {2(5)}$

$x=\frac{-2(+/-)√(64)} {10}$

$x=\frac{-2(+/-)8} {10}$

$x=\frac{-2(+)8} {10}=0.60$

$x=\frac{-2(-)8} {10}=-1$

therefore

The roots are -1 and 0.60