asked 207k views
0 votes
Which values, when placed in the box, would result in a system of equations with no solution? Select the four correct answers. y = –2x + 4 6x + 3y = –12 –4 0 4 12

asked
User Bcosynot
by
8.6k points

2 Answers

1 vote

Answer:

-12-4 0

Explanation:

answered
User Jens Timmerman
by
8.6k points
0 votes

Answer:

Explanation:

In order for the system of equations to have no solutions, the equations must be equivalent.

The answer can be solved by trial and error or by changing the second equation to the slope-intercept form and comparing it with the first equation.

If we let

6x + 3y = a

Then, the slope intercept form is:

y = -2x + a/3

Comparing the two equations, we equate the constant term:

a/3 = 4

a = 12

answered
User Timothy Alston
by
8.7k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.