Question

Find the perimeter of a square with an area of 702.25

Answer 1

area of a square= 702.25

A= side square

let's take side of a square= a

therefore,

702.25= a^2

a= √702.25 = 26.5

perimeter (P) of a square= 4a

P = 4x 26.5= 106

so perimeter of a square is 106