Which function has a range of (-pi/2,pi/2)

Question

asked Jun 8, 2020 148k views

2 Answers

Mcjudd · Answer 1 · 2020-06-14T05:13:15+0000

ANSWER

$y = \tan^( - 1) (x)$

EXPLANATION

The inverse tangent function has two horizontal asymptotes

$y=\pm (\pi)/(2)$

Therefore it has a range of

$( - (\pi)/(2),(\pi)/(2) )$

The second choice is the correct option.

Which function has a range of (-pi/2,pi/2)-example-1

Which function has a range of (-pi/2,pi/2)

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