Question

Solve equation for 0
Steps?

Answer 1

`\cos\theta=(\sqrt2)/(2)\\\\\cos(\pi)/(4)=(\sqrt2)/(2)\ \text{and}\ \cos\left(-(\pi)/(4)\right)=(\sqrt2)/(2)\\\\\text{The period of cosine is}\ 2\pi.\ \text{Therefore your answer is}\\\\\theta=(\pi)/(4)+2k\pi\ \vee\ \theta=-(\pi)/(4)+2k\pi\ for\ k\in\mathbb{Z}`