Question

A circular pool with a 10 foot diameter is surrounded by a deck. What is the area of the deck which surrounds the pool? use 3.14

Answer 1

`146.5 {ft}^(2)`

EXPLANATION

The circular pool has diameter,

`d = 10ft`

This means the radius is;

`r = (10)/(2) = 5ft`

The area of the pool is

`= \pi \: {r}^(2)`

`=(3.14) * {5}^(2)`

`= 78.5`

The area of the deck is equal to the area of the square minus area of circular pool.

`{15}^(2) - 78.5 = 146.5 {ft}^(2)`

Answer 2

146.5 sq. feet.

Explanation:

Area of the deck = Large Square (with 15 ft side) - Circular Pool (with radius 10/2=5)

Large Square area =
`s^2=(15)^2=225`

Circular Pool area =
`\pi r^2=\pi (5)^2=\pi (25)\\=25(3.14)\\=78.5`

Thus, area of deck surrounding pool =
`225-78.5=146.5` sq. feet