What is the quadratic equation when the given equation is: y = 6(x - 1) {}^(2) - 4 ​

Question

What is the quadratic equation when the given equation is:


`y = 6(x - 1) {}^(2) - 4`
​

Answer 1

`\bf y=6(x-1)^2-4\implies y=6(x-1)(x-1)-4 \\\\\\ y=6\stackrel{\mathbb{F~O~I~L}}{(x^2-2x+1)}-4\implies y=6x^2-12x+6-4\implies y=6x^2-12x+2`