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Factor completely 4n^2-28n+49

Factor completely 4n^2-28n+49
asked 233k views
12 votes
Factor completely 4n^2-28n+49

asked
User Amar Magar
by
8.1k points

2 Answers

8 votes

Answer:

Then it would be 4n squared + 21

Explanation:

answered
User Usobi
by
7.7k points
5 votes

Answer:

(2n - 7)^2

Explanation:

both 4n^2 and 49 are perfect squares so take their square roots and get 2n and 7

answered
User Patrick Dattilio
by
8.5k points
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