Question

Let a = x^2 plus 4. Use a to find the solutions for the following equation: (x^2 plus. 4)^2 plus 32 = 12x^2 plus 48 which of the following are solutions for x

Answer 1

0 or +-2

Explanation:

(x^2 + 4)^2 + 32 = 12x^2 + 48

=> x^4 + 8x^2 + 16 + 32 - 12x^2 - 48 = 0

=> x^4 - 4x^2 = 0

=> x^2(x^2 - 4) = 0

=> x^2 = 0 or 4

=> x = 0 or +-2