Question

PLEASE HELP!!!

The height of a triangle is twice the length of its base. The area of the triangle is 50 meters. Find the height and base to the nearest tenth of a meter.

Answer 1

Explanation:

substitute and solve:

100 = bh

100 = b(2b)

100 = 2b²

50 = b²

b = √50

b = √(25 * 2)

b = 5√2

solve for h:

h = 2b

h = 2(5√2)

h = 10√2

if you are told to round to 1 DP :

b ≈ 7.1 m

h ≈ 14.1 m

Answer 2

Explanation:

Formula

Area = 1/2 B*H

Givens

Area = 50 m^2

B = 2x

H = x

Solution

50 = 1/2 * 2x*x Cancel the 1/2 with the 2

50 = x^2 Switch and take the square root.

sqrt(x^2) = sqrt(50)

x = 7.071

Base = 7.071 which rounds to 7.1

height = 14.142 which rounds to 14.1