Question

Please help me with this ❤️

Answer 1

`2 {sin}^(2) x = sin \: x \\ 2 {sin}^(2) x - sin \: x = 0 \\ sin \: x \: (2 sinx - 1) = 0 \\ \\ now \: sin \: x \: = 0 \\ x \: = \: 0 \: or \: \pi \: or \: 2\pi \\ \\ from \: 2nd \: factor \\ 2sin \: x \: - 1 = 0 \\ sin \: x \: = (1)/(2) \\ x \: = (\pi)/(6)`